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Physics
Body of mass m is taken from the earth's surface to the height equal to twice the radius (R) of the earth. The change in potential energy of body will be :
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Q. Body of mass $m$ is taken from the earth's surface to the height equal to twice the radius $(R)$ of the earth. The change in potential energy of body will be :
NEET
NEET 2013
Gravitation
A
$ \frac{1}{3} mgR$
13%
B
$ 2\, mgR$
23%
C
$ \frac{2}{3} mgR$
59%
D
$ 3 \, mgR$
5%
Solution:
Change in PE = $ - \frac{GMm}{3R} - \left(- \frac{GMm}{R} \right)$
$ = \frac{2}{3} \frac{GMm}{R} = \frac{2}{3} mg R$