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Q. Body of mass $m$ is taken from the earth's surface to the height equal to twice the radius $(R)$ of the earth. The change in potential energy of body will be :

NEETNEET 2013Gravitation

Solution:

Change in PE = $ - \frac{GMm}{3R} - \left(- \frac{GMm}{R} \right)$
$ = \frac{2}{3} \frac{GMm}{R} = \frac{2}{3} mg R$