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Physics
Blood is flowing at the rate of 100 cm3 s- 1 in a capillary of cross-sectional area 0.25 m2 . The velocity of flow is
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Q. Blood is flowing at the rate of $100 \, cm^{3} \, s^{- 1}$ in a capillary of cross-sectional area $0.25 \, m^{2}$ . The velocity of flow is
NTA Abhyas
NTA Abhyas 2020
A
$1 \, mm \, s^{- 1}$
8%
B
$0.2 \, mm \, s^{- 1}$
17%
C
$0.3 \, mms^{- 1}$
25%
D
$0.4 \, mms^{- 1}$
50%
Solution:
For the blood flow in a capillary,
Volumetric flow rate = velocity \times area of cross-section
$Q=Av$
$ \, v=\frac{Q}{A}=\frac{100 \times 1 0^{- 6}}{0.25}$
$v=400 \, \times 10^{- 3} \, mms^{- 1}=0.4 \, mms^{- 1}$