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Q. Blood is flowing at the rate of $100 \, cm^{3} \, s^{- 1}$ in a capillary of cross-sectional area $0.25 \, m^{2}$ . The velocity of flow is

NTA AbhyasNTA Abhyas 2020

Solution:

For the blood flow in a capillary,
Volumetric flow rate = velocity \times area of cross-section
$Q=Av$
$ \, v=\frac{Q}{A}=\frac{100 \times 1 0^{- 6}}{0.25}$
$v=400 \, \times 10^{- 3} \, mms^{- 1}=0.4 \, mms^{- 1}$