Q.
Block of $3 \,kg$ is initially in equilibrium and is hanging by two identical springs $A$ and $B$ as shown in figures. If spring $A$ is cut from lower point at $t=0$ then, find acceleration of block in $ms ^{-2}$ at $t=0$.
Laws of Motion
Solution:
$k x=15$
after cut the spring $A$.
$a=\frac{3 g-k x}{3}=\frac{15}{3}=5\, m / s ^{2}$
