Q.
Block $B$ has mass $m$ and is released from rest when it is on top of wedge $A$, which has a mass $3\, m$. Determine the tension in cord $C D$ needed to hold the wedge from moving while $B$ is sliding down $A$. Neglect friction.
Laws of Motion
Solution:
$T=N \sin \theta$ and $N=m g \cos \theta$
$T=m g \cos \theta \sin \theta=\frac{m g}{2} \sin 2 \theta$
