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Q. Binding energy per nucleon for $C^{12}$ is $7.68MeV$ and for $C^{13}$ is $7.47MeV$ . The energy required to remove a neutron from $C^{13}$ is

NTA AbhyasNTA Abhyas 2020

Solution:

$\Delta \epsilon =13\times 7.47-12\times 7.68$
$=97.11-92.16$
$=4.95MeV$