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Tardigrade
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Physics
Binding energy per nucleon for C12 is 7.68MeV and for C13 is 7.47MeV . The energy required to remove a neutron from C13 is
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Q. Binding energy per nucleon for $C^{12}$ is $7.68MeV$ and for $C^{13}$ is $7.47MeV$ . The energy required to remove a neutron from $C^{13}$ is
NTA Abhyas
NTA Abhyas 2020
A
$4.95MeV$
B
$8.46MeV$
C
$9.45MeV$
D
$15.49MeV$
Solution:
$\Delta \epsilon =13\times 7.47-12\times 7.68$
$=97.11-92.16$
$=4.95MeV$