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Chemistry
BF3 reacts with NaH at 450 K to form NaF and X. When X reacts with LiH in diethyl ether. Y is formed. What is Y?
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Q. $BF_3$ reacts with $NaH$ at $450\, K$ to form $NaF$ and $X$. When $X$ reacts with $LiH$ in diethyl ether. Y is formed. What is Y?
AP EAMCET
AP EAMCET 2018
A
$LiBO_2$
13%
B
$Li_2B_4O_7$
13%
C
$LiBH_4$
47%
D
$B_2H_6\cdot LiH$
27%
Solution:
$2 BF _{3}+6 NaH \stackrel{450\, K }{\longrightarrow } 6 NaF + B _{2} H _{6}(X)$
$\underset{\text{Diborane}}{B _{2} H _{6}}+2 LiH \stackrel{\text { Diethyl ether }}{\longrightarrow } \underset{\text{Lithium boron hydride}}{2 LiBH _{4}(Y)}$