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Q. $BF_3$ reacts with $NaH$ at $450\, K$ to form $NaF$ and $X$. When $X$ reacts with $LiH$ in diethyl ether. Y is formed. What is Y?

AP EAMCETAP EAMCET 2018

Solution:

$2 BF _{3}+6 NaH \stackrel{450\, K }{\longrightarrow } 6 NaF + B _{2} H _{6}(X)$

$\underset{\text{Diborane}}{B _{2} H _{6}}+2 LiH \stackrel{\text { Diethyl ether }}{\longrightarrow } \underset{\text{Lithium boron hydride}}{2 LiBH _{4}(Y)}$