$\beta$-emission takes place from a radioactive nucleus as
${ }_{15}^{32} p \xrightarrow{-\beta}{ }_{16}^{32} S +{ }_{-1} e^{0}+\overline{ v }$
where $\bar{v}$ is the anti-neutrino.
$\ln \beta^{+}$ decay a positron is emitted as
${ }_{11}^{22} Na \rightarrow { }_{10}^{22} Ne +{ }_{+1} e^{0}+ v$
where $v$ is the neutrino.