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Q.
Benzoic acid is dissolved in benzene, van't Hoff factor will be
BHUBHU 2007
Solution:
When benzoic acid dissolve in benzene it will be dimerize due to the intermolecular hydrogen bonding
$2 C _{6} H _{5} COOH \xrightarrow{\text { benzene }} \left( C _{6} H _{5} COOH \right)_{2}$
van't Hoff factor $= \frac{\text { No. of particles after association or dissociation }}{\text { No. of particles before association or dissociation }} $
$=\frac{1}{2}=0.5$