Question

Benzene is resonance hybrid of mainly two Kekule structures. Hence,

• A. Half the molecules correspond to one structure and half to the second structure
• B. At low temperature benzene can be separated into two structures
• C. Two structures make equal contribution to resonance hybrid
• D. An individual benzene molecule changes back and forth between two structures

Answer 1

Answer: (C)

In Kekule's structure, the carbon atoms in benzene are arranged in a hexagonal ring with each carbon atom is attached to two other carbon atoms.
The ring contains alternate single and double bond.
These double bonds are due to the $\pi$ electrons present in benzene.
These $\pi$ electrons can delocalize and form two structures with different position of a double bond.
These are the resonance contributor. Thus, they contribute equally to form a resonance hybrid.