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Q. $ \left| \begin{matrix} x-2 & 2x-3 & 3x-4 \\ x-4 & 2x-9 & 3x-16 \\ x-8 & 2x-27 & 3x-64 \\ \end{matrix} \right|=0, $ then $ x $ is equal to:

KEAMKEAM 2004

Solution:

$ \left| \begin{matrix} x-2 & 2x-3 & 3x-4 \\ x-4 & 2x-9 & 3x-16 \\ x-8 & 2x-27 & 3x-64 \\ \end{matrix} \right|=0 $
In the given options only $ x=4 $ satisfy the given determinant.