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Q. Before equilibrium is set-up for the chemical reaction, $N_2O_4 \rightleftharpoons 2NO_2$, vapour density of the gaseous mixture was measured. If $D$ is the theoretical value of vapour density, variation of $x$ with $D/d$ is shown by the graph.
What is value of $D/d$ at point $Y$?Chemistry Question Image

Equilibrium

Solution:

$N_2O_{4(g)} \rightleftharpoons 2NO_{2(g)}$
Degree of dissociation, $x=\frac{D-d}{d}$ or $x=\frac{D}{d}-1$
At $Y, x=0$
$\therefore \frac{D}{d}-1=0$ or $\frac{D}{d}=1$