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Q. Based on the given diagram, which of the following statements regarding the solution of two miscible volatile liquids $A$ and $B$ are correct?
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(I) Plots $A C$ and $B D$ show that Raoult's law is obeyed for the solution in which $A$ is solute and $B$ is solvent and as well as for that in which $B$ is solute and $A$ is solvent.
(II) Plots $CD$ shows that Dalton's law of partial pressure is observed for the binary solution of components $A$ and $B$.
(III) In pure state, vapour pressures of volatile liquid differ by $50$ units.
(IV) Vapour pressure of a mixture containing $40 \%$ mole of $B$ is about $105$ units. Select the correct answer using the codes given below.

Solutions

Solution:

Figure shows ideal behaviour of solution.

At point $A , \chi_{ A }=0, \chi_{ B }=1$, thus

$A D=$ vapour pressure of pure $B=135$ units,

At point $B , \chi_{ B }=0, \chi_{ A }=1$, thus

$BC =$ vapour pressure of pure $A =85$ units

As $A$ is added into $B$, vapour pressure of $A$ decreases and that of $B$ increases.

Thus, $AC$ shows Raoult's law for a solution of $B$ in $A$(solvent)

and $BD$ shows Raoult's law for a solution of $A$ in $B$ (solvent).

Thus (I) is correct

Total vapour pressure at any composition is given by line $CD$,

thus (II) is correct.

$p_{B}^{o}-p_{A}^{o}=135-85=50$ units

Thus, (III) is correct. When,

$\chi_{ B }=0.4, \chi_{ A }=0.6$

Vapour pressure of the mixture is given by $CD$.

$p_{\text {total }}=p_{A}^{o} \chi_{A}+p_{B}^{o} \chi_{B}$

$=85 \times 0.6+135 \times 0.4=105$

It is same as given by graph.

Thus, (IV) is also correct.