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Q. Barium ions, $CN ^{-}$ and $Co ^{2+}$ form an ionic complex. If this complex is $75 \%$ ionised in aqueous solution with van't Hoff factor $(i)$ equal to four and paramagnetic moment is found equal to $1.73 \,BM$ (due to spin only) then, the hybridisation state of $Co (II)$ in the complex will be

Coordination Compounds

Solution:

$\alpha=\frac{i-1}{(n-1)} ; \frac{4-1}{(n-1)}=\frac{3}{4}$

So, $n=5,$ hence given complex must dissociate into five ions $= Ba _{3}\left[ Co ( CN )_{5}\right]_{2}$

Paramagnetic moment indicates one unpaired electron

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