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Q. $B \stackrel{\text { Lindlar/ } H _{2}}{\leftarrow} R C \equiv CR \stackrel{\text { Na/liq.NH }_{3}}{\longrightarrow } A, A$ and $B$ are geometrical isomers $(R- CH = CH -R)$ then

Hydrocarbons

Solution:

Lindlar's catalyst gives cis product thus $B$ is cis and Na/liq. $NH _{3}$ give trans product. Thus $A$ is trans.