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Q.
Average KE of $ C{{O}_{2}} $ at $ {{27}^{o}}C $ is E. The average kinetic energy of $ {{N}_{2}} $ at the same temperature will be
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Solution:
Average KE of a gas depends only on temperature. $ KE=\frac{3}{2}KT $ $ \therefore $ At the same temperature KE of $ C{{O}_{2}}=KE $ of $ {{N}_{2}}=E $