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  4. Atoms of an element Z form hexagonal closed packed (hcp) lattice and atoms of element X occupy all the tetrahedral voids. The formula of the compound is

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Q. Atoms of an element $Z$ form hexagonal closed packed (hcp) lattice and atoms of element $X$ occupy all the tetrahedral voids. The formula of the compound is

KVPYKVPY 2019The Solid State

Solution:

Number of lattice points in a $hcp$ lattice : number of tetrahedral voids is in $1 : 2$ ratio.
$\therefore $ Number of $Z $ atoms : $X$ atoms = $1 : 2$
$\therefore $ Formula of compound = $X_2Z$