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  4. Atomic number of Ag is 47 . In the same group, the atomic numbers of elements placed above and below Ag in long form of periodic table will be

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Q. Atomic number of $Ag$ is $47 .$ In the same group, the atomic numbers of elements placed above and below $Ag$ in long form of periodic table will be

Classification of Elements and Periodicity in Properties

Solution:

Silver belongs to $5^{\text {th }}$ period. So, the atomic number of elements placed above and below will be $47-18=29$ and $47+32=79$ respectively.