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  4. At which of the following temperatures would the molecules of a gas have twice the average kinetic energy they have at 20° C ?

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Q. At which of the following temperatures would the molecules of a gas have twice the average kinetic energy they have at $20^{\circ} C$ ?

Solution:

$E \propto T \therefore \frac{E_{2}}{E_{1}}=\frac{T_{2}}{T_{1}}$
$ \Rightarrow \frac{2 E_{1}}{E_{1}}=\frac{T_{2}}{(20+273)}$
$\Rightarrow T_{2}=293 \times 2=586\, K =313^{\circ} C$