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  4. At which height from the earth's surface does the acceleration due to gravity decrease by 75 % of its value at earth's surface?

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Q. At which height from the earth's surface does the acceleration due to gravity decrease by $75 \%$ of its value at earth's surface?

Gravitation

Solution:

$g_{\text {height }}=g / 4=\frac{ g }{\left(1+\frac{ h }{ R _{e}}\right)^{2}}$
$\Rightarrow h = R _{e}=6400\, km$