1. Tardigrade
  2. Question
  3. Chemistry
  4. At what temperature liquid water will be in equilibrium with water vapour? Δ Hvap - 40.73 kJ mol-1, Δ Svap = 0.109 kJ K-1 mol-1

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Q. At what temperature liquid water will be in equilibrium with water vapour?
$\Delta H_{vap} - 40.73 \,kJ\, mol^{-1}$, $\Delta S_{vap} = 0.109\, kJ\, K^{-1}\, mol^{-1}$

Thermodynamics

Solution:

At equilibrium $\Delta G = 0$ for $\Delta G = \Delta H - T\Delta S$
or $T = \frac{\Delta H}{\Delta S} = \frac{40.73}{0.109}$
$= 373.6\,K$