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  4. At what pH, the oxidation potential of Hydrogen gas electrode is 0.27V (Given: Pressure of H 2( g )=0.1 bar , (2.203 RT / F )=0.06 V )

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Q. At what $pH,$ the oxidation potential of Hydrogen gas electrode is $0.27V$ (Given: Pressure of $H _{2}( g )=0.1 bar , \frac{2.203 \quad RT }{ F }=0.06 V$ )

NTA AbhyasNTA Abhyas 2022

Solution:

$\frac{1}{2}H_{2}\left(\right.g\left.\right) \rightarrow H_{\left(\right. aq \left.\right)}^{+}+e^{-}$
$E_{H_{2} / H^{+}}=E_{H_{2} / H +}^\circ -\frac{0 . 06}{1}log\frac{\left[H^{+}\right]}{\left(P_{H_{2}}\right)^{1 / 2}}$
$0.27=0-\frac{0 . 06}{1}log\frac{\left[H^{+}\right]}{\left[\right. 0 . 1 \left]\right.^{1 / 2}}$
$\frac{9}{2}=-log\left[H^{+} \left(\right. aq \left.\right)\right]-\frac{1}{2}log\frac{1}{0 . 1},pH=5$