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Q. At what height above the earth’s surface, the value of $g$ is half of its value on earth’s surface? Given its radius is $6400\, km$.

JIPMERJIPMER 2019Gravitation

Solution:

Here gh = g/2
But gh $=g\left(\frac{R}{R+h}\right)^{^2}$
$\therefore \quad \frac{g}{2}=g\left(\frac{R}{R+h}\right)^{^2}$ or $\left(\frac{R}{R+h}\right)^{^2}=\frac{1}{2}$
or $\quad \frac{R+h}{R}=\sqrt{2}$
or $h=\left(\sqrt{2}-1\right)R = 0.414 R = 0.414 × 6400$
$= 2649.6$ km.