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Q. At what altitude $(h)$ above the earths surface would the acceleration due to gravity be one fourth of its value at the earths surface?
where, $R$ is the radius of the earth.

Delhi UMET/DPMTDelhi UMET/DPMT 2011Gravitation

Solution:

Given, $g'=\frac{g}{4}$
We know that is acceleration due to gravity at height $h$ from the surface of the earth
$g'=g\left[\frac{R}{R +h}\right]^{2}$
Hence $\frac{g}{4}=g\left[\frac{R}{R+ h}\right]^{2}$
$\left(\therefore g'=\frac{g}{4}\right)$
$\frac{R}{R +h}=\frac{1}{2}$
$R + h =2 R$
$h = R$