Question

At what absolute temperature the pressure of $He$ gas in a definite volume become equal to zero?

• A. $\frac{a}{R} \times \frac{\left(V_{ m }-b\right)^{2}}{V_{ m }^{2}}$
• B. $\frac{a}{R} \times \frac{\left(V_{ m }-b\right)}{V_{ m }^{2}}$
• C. $\frac{a}{R} \times \frac{\left(V_{ m }-b\right)^{2}}{V_{ m }}$
• D. $\frac{a V_{ m }}{R}$

Answer 1

Answer: (B)

$\left(P+\frac{a}{V_{ m }^{2}}\right)\left(v_{ m }-b\right)=R T$

when $P=O, T=\frac{a}{R} \times \frac{\left(v_{ m }-b\right)}{{V}_{ m }^{2}}$