Question

At the point of intersection of the two curves shown, calculate the concentration of $B$ in the first order reaction $A \rightarrow nB.$

• A. $\frac{\text{n} \text{A}_{0}}{2}$
• B. $\frac{\text{A}_{0}}{\text{n - 1}}$
• C. $\frac{\text{n} \text{A}_{0}}{\text{n} + 1}$
• D. $\left(\frac{\text{n} - 1}{\text{n} + 1}\right) \left(\text{ A}\right)_{0}$

Answer 1

Answer: (C)

According to question, at intersection point $\Rightarrow[ A ]=[ B ]$
$ \begin{array}{l} \Rightarrow A _{0}- x = nx \\ \Rightarrow A _{0}=( n +1) x \\ \Rightarrow x =\frac{ A _{0}}{ n +1} \end{array} $
$ [ B ]= nx $
$ =\left(\frac{ n \times A _{0}}{ n +1}\right) $