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Q.
At surface of earth weight of a person is $72 \,N$ then his weight at height $R/2$ from surface of earth is ($R =$ radius of earth)
Gravitation
Solution:
Weight of the body at height $R$,
$W' = W\left(\frac{R}{R+h}\right)^{2}$
$ = W\left(\frac{R}{R+\frac{R}{2}}\right)^{2} = W\left(\frac{2}{3}\right)^{2} $
$= \frac{4}{9} W = \frac{4}{9}\times72 = 32 \,N$