Question

At equilibrium, if $K_p = 1$, then

• A. $\Delta G^{\circ} > 1$
• B. $\Delta G^{\circ} < 1$
• C. $\Delta G^{\circ} = 0$
• D. $\Delta G^{\circ} = 1$

Answer 1

Answer: (C)

At equilibrium, the relation between free energy of the reaction and equilibrium constant is as follows.

$\Delta \,G^{\circ}=-R T$ ln $K_{p}$

If $ K_{p}=1$ at equilibrium

$\Delta\, G'=-R T $ ln $1$

or $\Delta G^{\circ}=0$