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Q. At a temperatur of $30^{\circ} C$, the susceptibility of a ferromagnetic material is found to be $\chi$. Its susceptibility at $333^{\circ} C$ is

Magnetism and Matter

Solution:

According to Curie's law, $\chi_{ m }=\frac{\mu_0 C }{ T }$
where $C$ is Curie constant,
$T =$ temperature
$\therefore \chi_{ m } \alpha \frac{1}{ T } $
$\frac{\chi_{ m _1}}{\chi_{ m _2}}=\frac{ T _2}{ T _1}=\frac{273+333}{273+30}=\frac{606}{303}=2 $
$\therefore \chi_{ m _2}=\chi_{ m _1} / 2=0.5 \chi_{ m _1}$
$=0.5 \chi\left(\because \chi_{ m _1}=\chi\right)$