1. Tardigrade
  2. Question
  3. Chemistry
  4. At a constant pressure p, the plot of volume (V) as a function of temperature (T) for 2 moles of an ideal gas gives a straight line with a slope 0.328 LK-14. The value of p (in atm) is closest to [Gas constant, R = 0.0821 L atm mol-1 K-1]

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Q. At a constant pressure $p$, the plot of volume $(V)$ as a function of temperature $(T)$ for $2$ moles of an ideal gas gives a straight line with a slope $0.328\, LK^{-1}4$. The value of p (in atm) is closest to [Gas constant, $R = 0.0821\, L$ atm $mol^{-1} K^{-1}$]

KVPYKVPY 2017

Solution:

According to ideal gas equation
$pV=nRT \Rightarrow \frac{V}{T}=\frac{nR}{p}=$slope
Given, slope $= 0.328, n = 2$
$\therefore p=\frac{nR}{slope}=\frac{2\times0.0821}{0.328}=0.500$ atm