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Chemistry
At a certain temperature, only 50 % HI is dissociated into H2 and I2 at equilibrium. The equilibrium constant is :
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Q. At a certain temperature, only $50\%$ $HI$ is dissociated into $H_2$ and $I_2$ at equilibrium. The equilibrium constant is :
JEE Main
JEE Main 2014
Equilibrium
A
1.0
17%
B
3.0
3%
C
0.5
19%
D
0.25
61%
Solution:
$\begin{array}{l} 2 HI \rightleftharpoons H _2+ I _2 \\ \text { a } 0 \quad 0 \\ a (1-0.5) \quad 0.25 a \quad 0.25 a \\ K =\frac{(0.25 a )(0.25 a )}{(0.5 a )^2} \\ K =0.25 \\ \end{array}$