1. Tardigrade
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  3. Physics
  4. At a certain place, the acceleration due to gravity is determined using a simple pendulum. The length of the pendulum is 25.0cm measured with an instrument with least count 0.1cm and a stopwatch with least count of 1s measures the time taken by the pendulum for 40 oscillations to be 50s . The accuracy in the measurement of g is

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Q. At a certain place, the acceleration due to gravity is determined using a simple pendulum. The length of the pendulum is $25.0cm$ measured with an instrument with least count $0.1cm$ and a stopwatch with least count of $1s$ measures the time taken by the pendulum for $40$ oscillations to be $50s$ . The accuracy in the measurement of $g$ is

NTA AbhyasNTA Abhyas 2022

Solution:

$g=\frac{4 \left(\pi \right)^{2} l}{T^{2}}\frac{Δg}{g}=\frac{2 ΔT}{T}+\frac{ΔL}{L};=2\left(\frac{1}{50}\right)+\frac{0 . 1}{25 . 0}=4.4\%$