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Q. At $ 90{}^\circ C, $ pure water has $ {{H}_{3}}{{O}^{+}} $ ion concentration of $ {{10}^{-6}}mol\text{/}L. $ The $ {{K}_{w}} $ at $ 90{}^\circ C $ is

CMC MedicalCMC Medical 2008

Solution:

$ {{K}_{w}}=[{{H}^{+}}]\,[O{{H}^{-}}] $ $ =({{10}^{-6}})\times ({{10}^{-6}}) $ $ (\because [{{H}^{+}}]=[O{{H}^{-}}]) $ $ ={{10}^{-12}} $