1. Tardigrade
  2. Question
  3. Chemistry
  4. At 700 K, the equilibrium constant Kp for the reaction 2 SO 3(g) leftharpoons 2 SO 2(g)+ O 2(g) is 1.80 × 10-3 k Pa. What is the numerical value of Kc in moles per litre for this reaction at the same temperature?

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Q. At $700\, K$, the equilibrium constant $K_{p}$ for the reaction
$2 SO _{3}(g) \rightleftharpoons 2 SO _{2}(g)+ O _{2}(g)$
is $1.80 \times 10^{-3} \,k \,Pa$. What is the numerical value of $K_{c}$ in moles per litre for this reaction at the same temperature?

Punjab PMETPunjab PMET 2010

Solution:

Here $n_{p}=3$ mol, $n_{r}=2$ mol
$\therefore \Delta n_{g} =n_{p}-n_{r}=3-2=1 .$ mol
$K_{p} =1.80 \times 10^{-3}\, k\,Pa $
$=1.80\, Pa =\frac{1.80}{10^{5}} $ bar
$=1.80 \times 10^{-5}$ bar
$\because K_{p}=K_{c}(R T)^{\Delta n_{g}}$
$K_{c}=\frac{K_{p}}{R T}$
$=\frac{1.80 \times 10^{-5} bar }{0.0821 \,L \,bar\, K ^{-1}\, mol ^{-1} \times 700\, K }$
$=3.13 \times 10^{-7} \,mol\, L ^{-1}$