1. Tardigrade
  2. Question
  3. Chemistry
  4. At 600° C , K p for the following reaction is 1 atm X(g) leftharpoons Y(g)+Z(g) at equilibrium, 50 % of X(g) is dissociated. The total pressure of the equilibrium system is P atm. What is the partial pressure (in atm) of X(g) at equilibrium?

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Q. At $600^{\circ} C , K _{ p }$ for the following reaction is $1 \,atm$
$X(g) \rightleftharpoons Y(g)+Z(g)$
at equilibrium, $50 \%$ of $X(g)$ is dissociated. The total pressure of the equilibrium system is $P$ atm. What is the partial pressure (in atm) of $X(g)$ at equilibrium?

Equilibrium

Solution:

image

$K_{p}=\frac{P_{y} \cdot P_{z}}{P_{x}}$

$1=\frac{\frac{ P }{3} \times \frac{ P }{3}}{\frac{ P }{3}}$

$\Rightarrow p =3 atm$

Partial pressure of $X=\frac{P}{3}=1$ atm