1. Tardigrade
  2. Question
  3. Chemistry
  4. At 40° C, the vapour pressure of pure liquids, benzene and toluene, are 160 mmHg and 60 mmHg respectively. At the same temperature, the vapour pressure of an equimolar solution of the two liquids, assuming the ideal solution should be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. At $40^{\circ} C$, the vapour pressure of pure liquids, benzene and toluene, are $160\, mmHg$ and $60\, mmHg$ respectively. At the same temperature, the vapour pressure of an equimolar solution of the two liquids, assuming the ideal solution should be

Solutions

Solution:

For ideal solution, $p_{\text {total }}=p_{1}^{\circ} x_{1}+p_{2}^{\circ} x_{2}$
$=160 \times \frac{1}{2}+60 \times \frac{1}{2}=110\, mmHg$