Question

At 3000 K, the equilibrium partial pressure of $CO_{2},CO \, and \, O_{2}$ are 0.6, 0.4 and 0.2 atm respectively. $K_{p}$ for the reaction, $2CO_{2}\rightleftharpoons2CO+O_{2}$ is

• A. 0.088
• B. 0.0533
• C. 0.133
• D. 0.177

Answer 1

Answer: (A)

$2\text{C}\text{O}_{2 \, }⇌ \, 2\text{C}\text{O}+\text{O}_{2}$
At equili. 0.6 atm 0.4 atm 0.2 atm
$\therefore $ $\text{K}_{\text{p}}=\frac{\text{p}_{\text{C} \text{O}}^{2} \times \text{p}_{\text{O}_{2}}}{\text{p}_{\text{C} \text{O}}^{2}_{2}}$
$ \, =\frac{\left(0.4\right)^{2} \left(\right. 0.2 \left.\right)}{\left(0.6\right)^{2}}=0.088$