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  4. At 300 K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of O2 for complete combustion and 40 mL of CO2 is formed. The formula of the hydrocarbon is :

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Q. At $300\, K$ and $1$ atmospheric pressure, $10\, mL$ of a hydrocarbon required $55\, mL$ of $O_2$ for complete combustion and $40\, mL$ of $CO_2$ is formed. The formula of the hydrocarbon is :

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Solution:

$C _{ x } H _{ y }+\left( x +\frac{ y }{4}\right) O _2 \longrightarrow xCO _2+\frac{ y }{2} H _2 O$
$1010\left(x+\frac{y}{4}\right) 10 x$
By given data, $10\left(x+\frac{y}{4}\right)=55 \ldots . .(1)$
$10 x=40 \ldots . .(2)$
$\therefore x=4, y=6 \Rightarrow C_4 H_6$