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  3. Chemistry
  4. At 298 K , the pH of 0.23 M weak acid H X (ionization constant =7.3 × 10-6 ) would be

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Q. At $298 K ,$ the $pH$ of $0.23 M$ weak acid $H X$ (ionization constant $=7.3 \times 10^{-6}$ ) would be

Equilibrium

Solution:

For weak acid; $\alpha=\sqrt{\frac{K_{a}}{C}}$

$\left[ H ^{+}\right]=C \times \alpha=\sqrt{K_{a} \times C}=\sqrt{7.3 \times 10^{-6} \times 0.23}=1.29 \times 10^{-3}$

$pH =-\log H ^{+}=\log \frac{1}{ H ^{+}}=\log \frac{1}{1.29 \times 10^{-3}}=2.88$