Question

At $298\, K$ temperature the activation energy for the reaction $x_{2}+y_{2} \rightarrow 2 x y+20\, kJ$ is $15\, kJ$. What will be the activation energy for the reaction $2 x y \rightarrow x_{2}+y_{2} ?$

• A. -15 kJ
• B. +35 kJ
• C. -5 kJ
• D. -35 kJ

Answer 1

Answer: (B)

$ \Delta_{R} H =$ activation energy of forward reaction - activation energy of backward reaction.
$\Rightarrow -20=15-?$
So, $+35\, kJ .$