Question

At 277 K, degree of dissociation water is $1\times 10^{- 7}\%$ . The value of ionic product of water is

• A. $3.0\times 10^{- 14}$
• B. $3.085\times 10^{- 15}$
• C. $1\times 10^{- 16}$
• D. $1\times 10^{- 14}$

Answer 1

Answer: (B)

The molar concentration of water

$=\frac{1000 \times 1}{18}=55.5\text{ M}$

$\alpha $ , the degree of dissociation $=\frac{1 \times 1 0^{- 7}}{100}$

$=1\times 10^{- 9}$



$K_{w}=C\alpha \times C\alpha $ or $C^{2}\alpha ^{2}$

$K_{w}=(55.5)^{2}\left(1 \times 10^{-9}\right)^{2}=3.085 \times 10^{-15}$