Question

At $ \text{27}{{\,}^{\text{o}}}\text{C} $ one mole of an ideal gas exerted a pressure of 0.821 atmosphere. What is its volume in liters ( $ \text{R = 0}\text{.0821}\,\,\text{L} $ atm $ \text{mo}{{\text{l}}^{-1}}{{K}^{-1}} $ ?

• A. 300
• B. 30
• C. 0.3
• D. 3

Answer 1

Answer: (B)

$ T=27+273=300K $ $ P=0.821\,\text{atm} $ $ V=? $ $ R=0.0821\,\text{Latm}\,\text{mo}{{\text{l}}^{-1}}\,{{\text{K}}^{-1}} $ $ n=1\,mol $ $ PV=nRT $ $ V=\frac{nRT}{P} $ $ =\frac{1\times 0.0821\times 300}{0.821}=30\,L $