Question

At $27^{\circ} C$ temperature, the kinetic energy of an ideal gas is $E_{1} .$ If the temperature is increased to $327^{\circ} C$, then kinetic energy would be

• A. $\frac{E_{1}}{2}$
• B. $\frac{E_{1}}{\sqrt{2}}$
• C. $\sqrt{2} E_{1}$
• D. $2 E_{1}$

Answer 1

Answer: (D)

Kinetic energy of an ideal gas,
$E_k = \frac{3}{2} RT $ or $E_k \propto T$
$\therefore E_{327} = E_{27} \frac{(327 + 273)}{(27 + 273)} = 2E_{27} = 2E_1$