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Q. At $27^{\circ} C$, a solution containing $2.5 \,g$ of solute in $250.0 \,mL$ of solution exerts an osmotic pressure of $400 \,Pa$. The molar mass of the solute is ____$g\,mol ^{-1}$ (Nearest integer)
(Given : $R =0.083 \,L\,bar\, K ^{-1} \,mol ^{-1}$ )

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Solution:

$= CRT $
$ \frac{400 Pa }{10^5}=\frac{\frac{2.5 g }{ M _{ o }}}{250 / 1000 L } \times 0.83 \frac{ L - bar }{ K \cdot mol } \times 300\, K $
$M _{ o }=62250$