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Q. At $120^{\circ}C$, the vapour pressure of pure chlorobenzene $(C_{6}H_{5}Cl)$ is $0.736\,atm$ What is the vapour pressure of a solution of 5.00 g of naphthalene $(C_{10}H_{8})$ in 50.0 g of chlorobenzene? (Assume that naphthalene is not volatile)

Solutions

Solution:

$\frac{0.736-P_{s}}{0.736}=\frac{\frac{5}{152}}{\frac{5}{152}+\frac{50}{112.5}}$
On solving $P_{s}=0.677 \,atm$