1. Tardigrade
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  3. Chemistry
  4. At 0°C, the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. The molecular mass of the oxide is

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Q. At $0^{\circ}C$, the density of a certain oxide of a gas at $2$ bar is same as that of dinitrogen at $5$ bar. The molecular mass of the oxide is

States of Matter

Solution:

$M_{oxide} = \frac{d_{\text{oxide}}RT}{P_{\text{oxide}}} ....$(i)
$M_{N_2} = \frac{d_{N_2}RT}{P_{N_2}} ....$(ii)
Dividing equation (1) by equation (2) gives
$\frac{M_{\text{oxide}}}{M_{N_2}} = \frac{d_{\text{oxide}} P_{N_2}}{ d_{N_2 }\times P_{oxide}}$
Given: $d_{oxide} = d_{N_2} \therefore M_{\text{oxide}} = \frac{5 bar}{2 bar} \times 28g$ mol$ ^{-1}$
$M_{\text{oxide}} = 70 g$ mol $^{-1}$