Question

At $0.1atm$ and $25^\circ C$ , compressibility factor of four gases $A,B,C$ and $D$ are $0.25,1.3,1$ and $0.7$ respectively. The gas which is most easily liquifiable at $25^\circ C$ , will be -

• A. $D\left(\right.g\left.\right)$
• B. $C\left(\right.g\left.\right)$
• C. $B\left(\right.g\left.\right)$
• D. $A\left(\right.g\left.\right)$

Answer 1

Answer: (D)

$Z < 1$ (negative deviation)
attraction force will dominate
so, $A\left(\right.g\left.\right)$ will be more compressible/liquifiable.