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Q. Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass m, when taken to a height h from the surface of earth (of radius R), is given by,

NEETNEET 2019Gravitation

Solution:

$\Delta U = -GMm [ \frac{1}{r_f} - \frac{1}{r_i}]$
$ = - GMm[\frac{1}{R+h} - \frac{1}{R}] $
$= \frac{GMmh}{R(R+h)}$