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Physics
Assuming diode forward voltage drop to be 0.3 V the voltage drop across A and B is
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Q. Assuming diode forward voltage drop to be $0.3 \,V$ the voltage drop across $A$ and $B$ is
A
2.3V
29%
B
1.3V
29%
C
0.5V
14%
D
zero
29%
Solution:
$V-0.3=0.2 \times 10^{-3} \times 10 \times 10^{3}=2$
$V=2.3 \,V$