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Chemistry
Assume that the nucleus of the fluorine atom is a sphere of radius 5 × 10-13 cm What is the density of matter in the nucleus?
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Q. Assume that the nucleus of the fluorine atom is a sphere of radius $5 \times 10^{-13} \,cm$ What is the density of matter in the nucleus?
Some Basic Concepts of Chemistry
A
$6.02 \times 10^{23} g / mL$
36%
B
$6.02 \times 10^{13} g / mL$
36%
C
$12.02 \times 10^{25} g / mL$
18%
D
$12.02 \times 10^{15} g / mL$
11%
Solution:
Mass of one fluorine nucleus $=\frac{19}{6.023 \times 10^{23}} \,g$
Volume of fluorine nucleus $=\frac{4}{3} \times \frac{22}{7} \times\left(5 \times 10^{-13}\right)^{3} cm ^{3}$
Density $=\frac{19}{6.023 \times 10^{23} \times \frac{4}{3} \times \frac{22}{7} \times 125 \times 10^{-39}}$
$=6.02 \times 10^{13} \, g / cm ^{3}$