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Q. Assume that the nucleus of the fluorine atom is a sphere of radius $5 \times 10^{-13} \,cm$ What is the density of matter in the nucleus?

Some Basic Concepts of Chemistry

Solution:

Mass of one fluorine nucleus $=\frac{19}{6.023 \times 10^{23}} \,g$

Volume of fluorine nucleus $=\frac{4}{3} \times \frac{22}{7} \times\left(5 \times 10^{-13}\right)^{3} cm ^{3}$

Density $=\frac{19}{6.023 \times 10^{23} \times \frac{4}{3} \times \frac{22}{7} \times 125 \times 10^{-39}}$

$=6.02 \times 10^{13} \, g / cm ^{3}$