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Q. Assume that the chances of a patient having a heart attack is $40 \%$. It is also assumed that a meditation and yoga course reduce the risk of heart attack by $30 \%$ and prescription of certain drug reduces its chances by $25 \%$. At a time a patient ean chouse any one of the two uplions with equal probabilities. It is given that after going through one of the two options the patient selected at random suffers a heart attack. The probability that the patient followed a course of meditation and yoga is

Probability - Part 2

Solution:

Let $A, E_{1}$, and $E_{2}$, respectively, denote the events that a person has a heart attack, the selected person followed the course of yoga and meditation, and the person adopted the drug prescription. Therefore,
$P(A)=0.40 ; \quad P\left(E_{1}\right)=P\left(E_{2}\right)=\frac{1}{2}$
$P\left(A| E_{1}\right)=0.40 \times 0.70=0.28 ; P\left(A | E_{2}\right)=0.40 \times 0.75=0.30$
Probability that the patient suffering a heart attack followed course of meditation and yoga is given by $P\left(E_{1} | A\right)$.
$P\left(E_{1} | A\right) =\frac{P\left(E_{1}\right) P\left(A| E_{1}\right)}{P\left(E_{1}\right) P\left(A | E_{1}\right)+P\left(E_{2}\right) P\left(A | E_{2}\right)} $
$=\frac{\frac{1}{2} \times 0.28}{\frac{1}{2} \times 0.28+\frac{1}{2} \times 0.30}=\frac{14}{29}$